The eccentricity of an ellipse whose centre is at the origin is ½. If one of its directrices is x = -4, then the equation of the normal to it at (1, 3/2) is

The eccentricity of an ellipse whose centre is at the origin is ½. If one of its directrices is x = -4, then the equation of the normal to it at (1, 3/2) is

The eccentricity of an ellipse whose centre is at the origin is ½. If one of its directrices is x = -4, then the equation of the normal to it at (1, 3/2) is

A- 2y - x = 2

B- 4x - 2y = 1

C - 4x + 2y = 7

D - x + 2y = 4

Solution:

Eccentricity = 1/2

Let 2a be the length of major axis and 2b be the length of minor axis

a/e = 4

a = 2

Also, b = √3, as e = 1/2

Equation of ellipse is x2/4 + y2/3 = 1

Equation of normal at (1, 3/2) is 4x - 2y = 1

The correct option is B.


18th March 2019

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