Two springs have their force constants as K1 and K2 (K1 > K2). On which spring is work done (i) when their lengths are increased by the same amount (ii) when they are stretched by the same force

Que 15. Two springs have their force constants as K1 and K2 (K1 > K2). On which spring is

Que 15. Two springs have their force constants as K1 and K2 (K1 > K2). On which spring is work done (i) when their lengths are increased by the same amount (ii) when they are stretched by the same force?

Ans- If each spring is stretched by x1 then,

work done on the first spring= ½ K1 X2

and work done on the second spring= ½ K2 x22 As K1 so, work done on the first spring is more.

Again, if same force say F be applied to the spring then, the extension in the first spring = x1=F/K1 and the extension is the second spring = x2= F/ K2 Thus work done on the 

Second spring=F2/2K1 and work done on the second spring =F2/2K2

So, we find in this case work done is more for stretching the second spring.

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10th November 2018

Aakashshaw

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