Find the minimum integral value of n such that the division 55n/124 leaves no remainder
As 55 does not have factor common to 124, so for 55n to be exactly divisible by 124, n should be a multiple of 124.
Hence the minimum value that n can have is 124 it self
The correct option is A.
A contract on construction job specifies a penalty for delay in completion of the work beyond a certain date is as follows: Rs. 200 for the first day, Rs. 250 for the second day, Rs. 300 for the third day, etc. The penalty for each succeeding day being 50 more than that of the preceding day. How much penalty should the contractor pay if he delays the work by 10 days?
Penalty follows Arithmetic Progression (AP) with
First term, a = 200
Common difference, d = 50
Number of terms, n = 10
Sum of AP = n/2 [2a + (n-1)d]
Sum = 10/2 [2*200 + (10-1)*50]
= 5 [400 + 450] = 4250
The correct option is B.